What is the tangent of f(x)= 1/((2x-1)^6),\at x=1 ?

The tangent of f(x)= 1/((2x-1)^6),\at x=1 is y=-12x+13

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tangent of f(x)= 1/((2x-1)^6),\at x=1

tangent of

f (x) = \frac{1}{( 2 x - 1 ) ^{6}}, at x = 1

y = - 12 x + 13

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = \frac{1}{( 2 x - 1 ) ^{6}} : \frac{df ( x )}{d x} = - \frac{12}{( 2 x - 1 ) ^{7}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 12

Find the line with slope m=

- 12

and passing through

(1, 1) : y = - 12 x + 13

y = - 12 x + 13

What is the tangent of f(x)= 1/((2x-1)^6),\at x=1 ?
The tangent of f(x)= 1/((2x-1)^6),\at x=1 is y=-12x+13