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Popular Calculus >

f^'(x)=x^2-5

Solution

f^{^{'}} (x) = x^{2} - 5

Solution

f (x) = \frac{x ^{3}}{3} - 5 x + c_{1}

Solution steps

f^{'} (x) = x^{2} - 5

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int x^{2} - 5 d x

\int x^{2} - 5 d x = \frac{x ^{3}}{3} - 5 x + c_{1}

f (x) = \frac{x ^{3}}{3} - 5 x + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=x^2-5 ?
The solution for f^'(x)=x^2-5 is f(x)=(x^3)/3-5x+c_{1}