What is the tangent of f(x)=2x^2-10x+9,(2,-3) ?

The tangent of f(x)=2x^2-10x+9,(2,-3) is y=-2x+1

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tangent of f(x)=2x^2-10x+9,(2,-3)

tangent of

f (x) = 2 x^{2} - 10 x + 9, (2, - 3)

y = - 2 x + 1

Solution steps

Find the slope of

f (x) = 2 x^{2} - 10 x + 9 : \frac{df ( x )}{d x} = 4 x - 10

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(2, - 3) : y = - 2 x + 1

y = - 2 x + 1

What is the tangent of f(x)=2x^2-10x+9,(2,-3) ?
The tangent of f(x)=2x^2-10x+9,(2,-3) is y=-2x+1