What is (\partial)/(\partial x)(cos(z)+xy^2) ?

The answer to (\partial)/(\partial x)(cos(z)+xy^2) is y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(cos(z)+xy^2)

\frac{\partial}{\partial x} (cos (z) + x y^{2})

y^{2}

Solution steps

\frac{\partial}{\partial x} (cos (z) + x y^{2})

Treat

z, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (cos (z)) + \frac{\partial}{\partial x} (x y^{2})

\frac{\partial}{\partial x} (cos (z)) = 0

\frac{\partial}{\partial x} (x y^{2}) = y^{2}

= 0 + y^{2}

Simplify

= y^{2}

What is (\partial)/(\partial x)(cos(z)+xy^2) ?
The answer to (\partial)/(\partial x)(cos(z)+xy^2) is y^2