What is the integral of 4x^3-2x^2 ?

The integral of 4x^3-2x^2 is x^4-(2x^3)/3+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 4x^3-2x^2

\int 4 x^{3} - 2 x^{2} d x

x^{4} - \frac{2 x ^{3}}{3} + C

Solution steps

\int 4 x^{3} - 2 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{3} d x - \int 2 x^{2} d x

\int 4 x^{3} d x = x^{4}

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

= x^{4} - \frac{2 x ^{3}}{3}

Add a constant to the solution

= x^{4} - \frac{2 x ^{3}}{3} + C