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Popular Calculus >

y^'-tan(x)=0

Solution

y^{^{'}} - tan (x) = 0

Solution

y = - ln (cos (x)) + c_{1}

Solution steps

y^{'} (x) - tan (x) = 0

Isolate

y^{'} (x) : y^{'} (x) = tan (x)

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int tan (x) d x

\int tan (x) d x = - ln (cos (x)) + c_{1}

y = - ln (cos (x)) + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'-tan(x)=0 ?
The solution for y^'-tan(x)=0 is y=-ln(cos(x))+c_{1}