What is the tangent of f(x)=(x^2+7)(5-x),\at x=0 ?

The tangent of f(x)=(x^2+7)(5-x),\at x=0 is y=-7x+35

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tangent of f(x)=(x^2+7)(5-x),\at x=0

tangent of

f (x) = (x^{2} + 7) (5 - x), at x = 0

y = - 7 x + 35

Solution steps

Find the tangent point:

(0, 35)

Find the slope of

f (x) = (x^{2} + 7) (5 - x) : \frac{df ( x )}{d x} = 10 x - 3 x^{2} - 7

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 7

Find the line with slope m=

- 7

and passing through

(0, 35) : y = - 7 x + 35

y = - 7 x + 35

What is the tangent of f(x)=(x^2+7)(5-x),\at x=0 ?
The tangent of f(x)=(x^2+7)(5-x),\at x=0 is y=-7x+35