What is the integral from 1 to 2 of sin(x) ?

The integral from 1 to 2 of sin(x) is -cos(2)+cos(1)

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integral from 1 to 2 of sin(x)

\int_{1}^{2} sin (x) d x

- cos (2) + cos (1)

Decimal

0.95644 \dots

Solution steps

\int_{1}^{2} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{1}^{2}

Compute the boundaries:

- cos (2) + cos (1)

= - cos (2) + cos (1)

What is the integral from 1 to 2 of sin(x) ?
The integral from 1 to 2 of sin(x) is -cos(2)+cos(1)