What is (\partial)/(\partial x)(x^2+w^2) ?

The answer to (\partial)/(\partial x)(x^2+w^2) is 2x

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(\partial)/(\partial x)(x^2+w^2)

\frac{\partial}{\partial x} (x^{2} + w^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + w^{2})

Treat

w

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (w^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (w^{2}) = 0

= 2 x + 0

Simplify

= 2 x

What is (\partial)/(\partial x)(x^2+w^2) ?
The answer to (\partial)/(\partial x)(x^2+w^2) is 2x