(\partial)/(\partial x)(4xsin(7x^2y))

Lösung

\frac{\partial}{\partial x} (4 x sin (7 x^{2} y))

4 (sin (7 x^{2} y) + 14 x^{2} y cos (7 x^{2} y))

Schritte zur Lösung

\frac{\partial}{\partial x} (4 x sin (7 x^{2} y))

Behandle

y

als Konstante

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (x sin (7 x^{2} y))

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = sin (7 x^{2} y)

= 4 (\frac{\partial}{\partial x} (x) sin (7 x^{2} y) + \frac{\partial}{\partial x} (sin (7 x^{2} y)) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (sin (7 x^{2} y)) = cos (7 x^{2} y) \cdot 14 y x

= 4 (1 \cdot sin (7 x^{2} y) + cos (7 x^{2} y) \cdot 14 y xx)

Vereinfache

4 (1 \cdot sin (7 x^{2} y) + cos (7 x^{2} y) \cdot 14 y xx) : 4 (sin (7 x^{2} y) + 14 x^{2} y cos (7 x^{2} y))

= 4 (sin (7 x^{2} y) + 14 x^{2} y cos (7 x^{2} y))

\frac{d}{d x} (x (x - 1) (x - 2))

d er i v a t i v e y = 7 x

y^{^{'}} + 5 y = t e^{(4 t)}

\frac{\partial}{\partial x} (3 x^{2} - 4)

\int \frac{9}{9 + e ^{x}} d x