What is the tangent of (x+2)^2+(y-3)^2=37,(-8,4) ?

The tangent of (x+2)^2+(y-3)^2=37,(-8,4) is y=6x+52

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tangent of (x+2)^2+(y-3)^2=37,(-8,4)

tangent of

(x + 2)^{2} + (y - 3)^{2} = 37, (- 8, 4)

y = 6 x + 52

Solution steps

Find the slope of

(x + 2)^{2} + (y - 3)^{2} = 37 : \frac{d y}{d x} = - \frac{x + 2}{y - 3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(- 8, 4) : y = 6 x + 52

y = 6 x + 52

What is the tangent of (x+2)^2+(y-3)^2=37,(-8,4) ?
The tangent of (x+2)^2+(y-3)^2=37,(-8,4) is y=6x+52