What is the derivative of 0.8cos(x+0.5sin(2x)) ?

The derivative of 0.8cos(x+0.5sin(2x)) is -0.8sin(x)+cos(2x)

What is the first derivative of 0.8cos(x+0.5sin(2x)) ?

The first derivative of 0.8cos(x+0.5sin(2x)) is -0.8sin(x)+cos(2x)

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\frac{d}{d x} (0.8 cos (x) + 0.5 sin (2 x))

- 0.8 sin (x) + cos (2 x)

Solution steps

\frac{d}{d x} (0.8 cos (x) + 0.5 sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (0.8 cos (x)) + \frac{d}{d x} (0.5 sin (2 x))

\frac{d}{d x} (0.8 cos (x)) = - 0.8 sin (x)

\frac{d}{d x} (0.5 sin (2 x)) = cos (2 x)

= - 0.8 sin (x) + cos (2 x)

What is the derivative of 0.8cos(x+0.5sin(2x)) ?
The derivative of 0.8cos(x+0.5sin(2x)) is -0.8sin(x)+cos(2x)
What is the first derivative of 0.8cos(x+0.5sin(2x)) ?
The first derivative of 0.8cos(x+0.5sin(2x)) is -0.8sin(x)+cos(2x)