What is (\partial)/(\partial x)(sin(xy)+xcos(y)) ?

The answer to (\partial)/(\partial x)(sin(xy)+xcos(y)) is cos(xy)y+cos(y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(sin(xy)+xcos(y))

\frac{\partial}{\partial x} (sin (x y) + x cos (y))

cos (x y) y + cos (y)

Solution steps

\frac{\partial}{\partial x} (sin (x y) + x cos (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (sin (x y)) + \frac{\partial}{\partial x} (x cos (y))

\frac{\partial}{\partial x} (sin (x y)) = cos (x y) y

\frac{\partial}{\partial x} (x cos (y)) = cos (y)

= cos (x y) y + cos (y)

What is (\partial)/(\partial x)(sin(xy)+xcos(y)) ?
The answer to (\partial)/(\partial x)(sin(xy)+xcos(y)) is cos(xy)y+cos(y)