What is the derivative of (-1/x) ?

The derivative of (-1/x) is 1/(x^2)

What is the first derivative of (-1/x) ?

The first derivative of (-1/x) is 1/(x^2)

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\frac{d}{d x} (\frac{- 1}{x})

\frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{- 1}{x})

Simplify

\frac{- 1}{x} : - \frac{1}{x}

= \frac{d}{d x} (- \frac{1}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - (- 1 \cdot x^{- 1 - 1})

Simplify

- (- 1 \cdot x^{- 1 - 1}) : \frac{1}{x ^{2}}

= \frac{1}{x ^{2}}

What is the derivative of (-1/x) ?
The derivative of (-1/x) is 1/(x^2)
What is the first derivative of (-1/x) ?
The first derivative of (-1/x) is 1/(x^2)