What is the integral of (6ln^2(x))/x ?

The integral of (6ln^2(x))/x is 2ln^3(x)+C

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integral of (6ln^2(x))/x

\int \frac{6 ln ^{2} ( x )}{x} d x

2 ln^{3} (x) + C

Solution steps

\int \frac{6 ln ^{2} ( x )}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int \frac{ln ^{2} ( x )}{x} d x

Apply u-substitution

= 6 \cdot \int u^{2} d u

Apply the Power Rule

= 6 \cdot \frac{u ^{3}}{3}

Substitute back

u = ln (x)

= 6 \cdot \frac{ln ^{3} ( x )}{3}

Simplify

6 \cdot \frac{ln ^{3} ( x )}{3} : 2 ln^{3} (x)

= 2 ln^{3} (x)

Add a constant to the solution

= 2 ln^{3} (x) + C

What is the integral of (6ln^2(x))/x ?
The integral of (6ln^2(x))/x is 2ln^3(x)+C