What is the integral of xcos(bx) ?

The integral of xcos(bx) is 1/(b^2)(bxsin(bx)+cos(bx))+C

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integral of xcos(bx)

\int x cos (b x) d x

\frac{1}{b ^{2}} (b x sin (b x) + cos (b x)) + C

Solution steps

\int x cos (b x) d x

Apply u-substitution

= \int \frac{u cos ( u )}{b ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{b ^{2}} \cdot \int u cos (u) d u

Apply Integration By Parts

= \frac{1}{b ^{2}} (u sin (u) - \int sin (u) d u)

\int sin (u) d u = - cos (u)

= \frac{1}{b ^{2}} (u sin (u) - (- cos (u)))

Substitute back

u = b x

= \frac{1}{b ^{2}} (b x sin (b x) - (- cos (b x)))

Simplify

= \frac{1}{b ^{2}} (b x sin (b x) + cos (b x))

Add a constant to the solution

= \frac{1}{b ^{2}} (b x sin (b x) + cos (b x)) + C

What is the integral of xcos(bx) ?
The integral of xcos(bx) is 1/(b^2)(bxsin(bx)+cos(bx))+C