What is the solution for 9y^{''}+6y=0 ?

The solution for 9y^{''}+6y=0 is y=c_{1}cos(sqrt(2/3)t)+c_{2}sin(sqrt(2/3)t)

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9y^{''}+6y=0

9 y^{^{''}} + 6 y = 0

y = c_{1} cos (\frac{2}{3} t) + c_{2} sin (\frac{2}{3} t)

Solution steps

9 y^{''} (t) + 6 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{2}{3} t) + c_{2} sin (\frac{2}{3} t)

y = c_{1} cos (\frac{2}{3} t) + c_{2} sin (\frac{2}{3} t)

What is the solution for 9y^{''}+6y=0 ?
The solution for 9y^{''}+6y=0 is y=c_{1}cos(sqrt(2/3)t)+c_{2}sin(sqrt(2/3)t)