What is the d/(dt)(3sin^3(t)) ?

The d/(dt)(3sin^3(t)) is 9sin^2(t)cos(t)

What is the first d/(dt)(3sin^3(t)) ?

The first d/(dt)(3sin^3(t)) is 9sin^2(t)cos(t)

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\frac{d}{d t} (3 sin^{3} (t))

9 sin^{2} (t) cos (t)

Solution steps

\frac{d}{d t} (3 sin^{3} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (sin^{3} (t))

Apply the chain rule:

3 (sin (t))^{2} \frac{d}{d t} (sin (t))

= 3 (sin (t))^{2} \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 3 \cdot 3 (sin (t))^{2} cos (t)

Simplify

= 9 sin^{2} (t) cos (t)

What is the d/(dt)(3sin^3(t)) ?
The d/(dt)(3sin^3(t)) is 9sin^2(t)cos(t)
What is the first d/(dt)(3sin^3(t)) ?
The first d/(dt)(3sin^3(t)) is 9sin^2(t)cos(t)