What is laplacetransform e^{3a-bt} ?

The answer to laplacetransform e^{3a-bt} is (e^{3a})/(s+b)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

laplacetransform e^{3a-bt}

laplace transform

e^{3 a - b t}

\frac{e ^{3 a}}{s + b}

Solution steps

L {e^{3 a - b t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{3 a} L {e^{- b t}}

L {e^{- b t}} : \frac{1}{s + b}

= e^{3 a} \frac{1}{s + b}

Refine

e^{3 a} \frac{1}{s + b} : \frac{e ^{3 a}}{s + b}

= \frac{e ^{3 a}}{s + b}

What is laplacetransform e^{3a-bt} ?
The answer to laplacetransform e^{3a-bt} is (e^{3a})/(s+b)