What is the tangent of y=x^2-3,(5,22) ?

The tangent of y=x^2-3,(5,22) is y=10x-28

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of y=x^2-3,(5,22)

tangent of

y = x^{2} - 3, (5, 22)

y = 10 x - 28

Solution steps

Find the slope of

y = x^{2} - 3 : \frac{d y}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 10

Find the line with slope m=

10

and passing through

(5, 22) : y = 10 x - 28

y = 10 x - 28

What is the tangent of y=x^2-3,(5,22) ?
The tangent of y=x^2-3,(5,22) is y=10x-28