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Popular Calculus >

y^'=-50ky+k

Solution

y^{^{'}} = - 50 k y + k

Solution

y = \frac{e ^{- 50 k t - c_{1}}}{50} + \frac{1}{50}

Solution steps

y^{'} (t) = - 50 k y + k

Solve separable ODE:

y = \frac{e ^{- 50 k t - c_{1}}}{50} + \frac{1}{50}

y = \frac{e ^{- 50 k t - c_{1}}}{50} + \frac{1}{50}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=-50ky+k ?
The solution for y^'=-50ky+k is y=(e^{-50kt-c_{1}})/(50)+1/50