What is the derivative of y=t^3-2t+4 ?

The derivative of y=t^3-2t+4 is 3t^2-2

What is the first derivative of y=t^3-2t+4 ?

The first derivative of y=t^3-2t+4 is 3t^2-2

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derivative of

y = t^{3} - 2 t + 4

3 t^{2} - 2

Solution steps

\frac{d}{d t} (t^{3} - 2 t + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{3}) - \frac{d}{d t} (2 t) + \frac{d}{d t} (4)

\frac{d}{d t} (t^{3}) = 3 t^{2}

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (4) = 0

= 3 t^{2} - 2 + 0

Simplify

= 3 t^{2} - 2

What is the derivative of y=t^3-2t+4 ?
The derivative of y=t^3-2t+4 is 3t^2-2
What is the first derivative of y=t^3-2t+4 ?
The first derivative of y=t^3-2t+4 is 3t^2-2