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Popular Calculus >

y^'+7y=1

Solution

y^{^{'}} + 7 y = 1

Solution

y = - \frac{e ^{- 7 t - c_{1}}}{7} + \frac{1}{7}

Solution steps

y^{'} (t) + 7 y = 1

Solve separable ODE:

y = - \frac{e ^{- 7 t - c_{1}}}{7} + \frac{1}{7}

y = - \frac{e ^{- 7 t - c_{1}}}{7} + \frac{1}{7}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+7y=1 ?
The solution for y^'+7y=1 is y=-(e^{-7t-c_{1}})/7+1/7