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Popular Calculus >

f(x)= 1/(x^2-9)

Solution

f (x) = \frac{1}{x ^{2} - 9}

Solution

Domain : x < - 3 or - 3 < x < 3 or x > 3

Range : f (x) \leq - \frac{1}{9} or f (x) > 0

Y Intercepts : (0, - \frac{1}{9})

Asymptotes : Vertical x = - 3, x = 3, Horizontal y = 0

Extreme Points : Maximum (0, - \frac{1}{9})

+1

Interval Notation

Domain : (- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Range : (- \infty, - \frac{1}{9}] \cup (0, \infty)

Solution steps

Domain of

\frac{1}{x ^{2} - 9} : x < - 3 or - 3 < x < 3 or x > 3

Range of

\frac{1}{x ^{2} - 9} : f (x) \leq - \frac{1}{9} or f (x) > 0

Axis interception points of

\frac{1}{x ^{2} - 9} :

Y Intercepts

: (0, - \frac{1}{9})

Asymptotes of

\frac{1}{x ^{2} - 9} :

Vertical

: x = - 3, x = 3,

Horizontal

: y = 0

Extreme Points of

\frac{1}{x ^{2} - 9} :

Maximum

(0, - \frac{1}{9})

Graph

Popular Examples

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Frequently Asked Questions (FAQ)

What is the f(x)= 1/(x^2-9) ?
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