What is area f(x)=x^2-4,y=0,x=-4,x=3 ?

The answer to area f(x)=x^2-4,y=0,x=-4,x=3 is 71/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

area f(x)=x^2-4,y=0,x=-4,x=3

area

f (x) = x^{2} - 4, y = 0, x = - 4, x = 3

\frac{71}{3}

Decimal

23.66666 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{3} x^{2} - 4 d x

Solve

\int_{- 4}^{3} x^{2} - 4 d x : \frac{71}{3}

The area is:

= \frac{71}{3}

What is area f(x)=x^2-4,y=0,x=-4,x=3 ?
The answer to area f(x)=x^2-4,y=0,x=-4,x=3 is 71/3