What is the integral from 0 to 8 of xsqrt(1+x) ?

The integral from 0 to 8 of xsqrt(1+x) is 1192/15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 8 of xsqrt(1+x)

\int_{0}^{8} x 1 + x d x

\frac{1192}{15}

Decimal

79.46666 \dots

Solution steps

\int_{0}^{8} x 1 + x d x

Apply u-substitution

= \int_{1}^{9} (u - 1) u d u

Expand

(u - 1) u : u^{\frac{3}{2}} - u

= \int_{1}^{9} u^{\frac{3}{2}} - u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{9} u^{\frac{3}{2}} d u - \int_{1}^{9} u d u

\int_{1}^{9} u^{\frac{3}{2}} d u = \frac{484}{5}

\int_{1}^{9} u d u = \frac{52}{3}

= \frac{484}{5} - \frac{52}{3}

Simplify

\frac{484}{5} - \frac{52}{3} : \frac{1192}{15}

= \frac{1192}{15}

What is the integral from 0 to 8 of xsqrt(1+x) ?
The integral from 0 to 8 of xsqrt(1+x) is 1192/15