derivative of (x^3/(39)+(13)/(4x))

Lösung

\frac{d}{d x} (\frac{x ^{3}}{39} + \frac{13}{4 x})

\frac{x ^{2}}{13} - \frac{13}{4 x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{3}}{39} + \frac{13}{4 x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{39}) + \frac{d}{d x} (\frac{13}{4 x})

\frac{d}{d x} (\frac{x ^{3}}{39}) = \frac{x ^{2}}{13}

\frac{d}{d x} (\frac{13}{4 x}) = - \frac{13}{4 x ^{2}}

= \frac{x ^{2}}{13} - \frac{13}{4 x ^{2}}

d er i v a t i v e f (x) = \frac{2}{t ^{3}}

im pl i c i t \frac{d ^{2} y}{d x ^{2}}, x^{2} + y^{2} = 16

\frac{\partial}{\partial z} (x y + yz - x z)

1 - y^{2} d x = 1 - x^{2} d y

x \to 0 lim (\frac{- 2 e ^{- x}}{2 x - 2})