What is the solution for y^'=(1-2x)y^2,y(0)=-1/30 ?

The solution for y^'=(1-2x)y^2,y(0)=-1/30 is y=-1/(x-x^2+30)

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y^'=(1-2x)y^2,y(0)=-1/30

y^{^{'}} = (1 - 2 x) y^{2}, y (0) = - \frac{1}{30}

y = - \frac{1}{x - x ^{2} + 30}

Solution steps

y^{'} (x) = (1 - 2 x) y^{2}

Solve separable ODE:

y = - \frac{1}{x - x ^{2} + 30}

y = - \frac{1}{x - x ^{2} + 30}

What is the solution for y^'=(1-2x)y^2,y(0)=-1/30 ?
The solution for y^'=(1-2x)y^2,y(0)=-1/30 is y=-1/(x-x^2+30)