What is the integral of (cos(2x))/(1+sin^2(2x)) ?

The integral of (cos(2x))/(1+sin^2(2x)) is 1/2 arctan(sin(2x))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (cos(2x))/(1+sin^2(2x))

\int \frac{cos ( 2 x )}{1 + sin ^{2} ( 2 x )} d x

\frac{1}{2} arctan (sin (2 x)) + C

Solution steps

\int \frac{cos ( 2 x )}{1 + sin ^{2} ( 2 x )} d x

Apply u-substitution

= \int \frac{cos ( u )}{2 ( 1 + sin ^{2} ( u ) )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{cos ( u )}{1 + sin ^{2} ( u )} d u

Apply u-substitution

= \frac{1}{2} \cdot \int \frac{1}{1 + v ^{2}} d v

Use the common integral:

\int \frac{1}{1 + v ^{2}} d v = arctan (v)

= \frac{1}{2} arctan (v)

Substitute back

= \frac{1}{2} arctan (sin (2 x))

Add a constant to the solution

= \frac{1}{2} arctan (sin (2 x)) + C

What is the integral of (cos(2x))/(1+sin^2(2x)) ?
The integral of (cos(2x))/(1+sin^2(2x)) is 1/2 arctan(sin(2x))+C