What is the integral of (2-3/(x^{10)}) ?

The integral of (2-3/(x^{10)}) is 2x+1/(3x^9)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (2-3/(x^{10)})

\int (2 - \frac{3}{x ^{10}}) d x

2 x + \frac{1}{3 x ^{9}} + C

Solution steps

\int 2 - \frac{3}{x ^{10}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 d x - \int \frac{3}{x ^{10}} d x

\int 2 d x = 2 x

\int \frac{3}{x ^{10}} d x = - \frac{1}{3 x ^{9}}

= 2 x - (- \frac{1}{3 x ^{9}})

Simplify

= 2 x + \frac{1}{3 x ^{9}}

Add a constant to the solution

= 2 x + \frac{1}{3 x ^{9}} + C

What is the integral of (2-3/(x^{10)}) ?
The integral of (2-3/(x^{10)}) is 2x+1/(3x^9)+C