What is the tangent of (3x)/(x+1) ?

The tangent of (3x)/(x+1) is y= 3/((a_{0)+1)^2}x+(3a_{0}^2)/((a_{0)+1)^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of (3x)/(x+1)

tangent of

\frac{3 x}{x + 1}

y = \frac{3}{( a _{0} + 1 ) ^{2}} x + \frac{3 a _{0}^{2}}{( a _{0} + 1 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{3 a _{0}}{a _{0} + 1})

Find the slope of

y = \frac{3 x}{x + 1} : \frac{d y}{d x} = \frac{3}{( x + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{( a _{0} + 1 ) ^{2}}

Find the line with slope m=

\frac{3}{( a _{0} + 1 ) ^{2}}

and passing through

(a_{0}, \frac{3 a _{0}}{a _{0} + 1}) : y = \frac{3}{( a _{0} + 1 ) ^{2}} x + \frac{3 a _{0}^{2}}{( a _{0} + 1 ) ^{2}}

y = \frac{3}{( a _{0} + 1 ) ^{2}} x + \frac{3 a _{0}^{2}}{( a _{0} + 1 ) ^{2}}

What is the tangent of (3x)/(x+1) ?
The tangent of (3x)/(x+1) is y= 3/((a_{0)+1)^2}x+(3a_{0}^2)/((a_{0)+1)^2}