What is the solution for 2xydy+(x^2-y^2)dx=0 ?

The solution for 2xydy+(x^2-y^2)dx=0 is y=sqrt(-x^2+c_{1)x},y=-sqrt(-x^2+c_{1)x}

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2xydy+(x^2-y^2)dx=0

2 x y d y + (x^{2} - y^{2}) d x = 0

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

Solution steps

2 x y d y + (x^{2} - y^{2}) d x = 0

Solve Bernoulli ODE:

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

y = - x^{2} + c_{1} x, y = - - x^{2} + c_{1} x

What is the solution for 2xydy+(x^2-y^2)dx=0 ?
The solution for 2xydy+(x^2-y^2)dx=0 is y=sqrt(-x^2+c_{1)x},y=-sqrt(-x^2+c_{1)x}