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sum from n=0 to infinity of (100)/ntangent of f(x)= 4/(sqrt(x)),\at x= 1/4tangent of \sqrt[5]{2x^3+8x}(2.2)limit as n approaches infinity of 5ne^{-n}sum from n=1 to infinity of 4/(2^n)
Frequently Asked Questions (FAQ)
What is the limit as x approaches 2 of 3 ?
The limit as x approaches 2 of 3 is 3