What is the derivative of f(x)=-2x^2-20x-48 ?

The derivative of f(x)=-2x^2-20x-48 is -4x-20

What is the first derivative of f(x)=-2x^2-20x-48 ?

The first derivative of f(x)=-2x^2-20x-48 is -4x-20

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derivative of

f (x) = - 2 x^{2} - 20 x - 48

- 4 x - 20

Solution steps

\frac{d}{d x} (- 2 x^{2} - 20 x - 48)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (20 x) - \frac{d}{d x} (48)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (20 x) = 20

\frac{d}{d x} (48) = 0

= - 4 x - 20 - 0

Simplify

= - 4 x - 20

What is the derivative of f(x)=-2x^2-20x-48 ?
The derivative of f(x)=-2x^2-20x-48 is -4x-20
What is the first derivative of f(x)=-2x^2-20x-48 ?
The first derivative of f(x)=-2x^2-20x-48 is -4x-20