What is the integral of (2x^2+4x-6)/x ?

The integral of (2x^2+4x-6)/x is x^2+4x-6ln|x|+C

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integral of (2x^2+4x-6)/x

\int \frac{2 x ^{2} + 4 x - 6}{x} d x

x^{2} + 4 x - 6 ln ∣ x ∣ + C

Solution steps

\int \frac{2 x ^{2} + 4 x - 6}{x} d x

Expand

\frac{2 x ^{2} + 4 x - 6}{x} : 2 x + 4 - \frac{6}{x}

= \int 2 x + 4 - \frac{6}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x d x + \int 4 d x - \int \frac{6}{x} d x

\int 2 x d x = x^{2}

\int 4 d x = 4 x

\int \frac{6}{x} d x = 6 ln ∣ x ∣

= x^{2} + 4 x - 6 ln ∣ x ∣

Add a constant to the solution

= x^{2} + 4 x - 6 ln ∣ x ∣ + C

What is the integral of (2x^2+4x-6)/x ?
The integral of (2x^2+4x-6)/x is x^2+4x-6ln|x|+C