What is area y= 3/x ,y= 3/(x^2),x=4 ?

The answer to area y= 3/x ,y= 3/(x^2),x=4 is 6ln(2)-9/4

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area y= 3/x ,y= 3/(x^2),x=4

area

y = \frac{3}{x}, y = \frac{3}{x ^{2}}, x = 4

6 ln (2) - \frac{9}{4}

Decimal

1.90888 \dots

Solution steps

Apply the area formula:

\int_{1}^{4} \frac{3}{x} - \frac{3}{x ^{2}} d x

Solve

\int_{1}^{4} \frac{3}{x} - \frac{3}{x ^{2}} d x : 6 ln (2) - \frac{9}{4}

The area is:

= 6 ln (2) - \frac{9}{4}

What is area y= 3/x ,y= 3/(x^2),x=4 ?
The answer to area y= 3/x ,y= 3/(x^2),x=4 is 6ln(2)-9/4