What is the solution for (dy)/(dt)+3y=cos(2t) ?

The solution for (dy)/(dt)+3y=cos(2t) is y=(2sin(2t))/(13)+(3cos(2t))/(13)+(c_{1})/(e^{3t)}

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(dy)/(dt)+3y=cos(2t)

\frac{d y}{d t} + 3 y = cos (2 t)

y = \frac{2 sin ( 2 t )}{13} + \frac{3 cos ( 2 t )}{13} + \frac{c _{1}}{e ^{3 t}}

Solution steps

\frac{d y}{d t} + 3 y = cos (2 t)

Solve linear ODE:

y = \frac{2 sin ( 2 t )}{13} + \frac{3 cos ( 2 t )}{13} + \frac{c _{1}}{e ^{3 t}}

y = \frac{2 sin ( 2 t )}{13} + \frac{3 cos ( 2 t )}{13} + \frac{c _{1}}{e ^{3 t}}

What is the solution for (dy)/(dt)+3y=cos(2t) ?
The solution for (dy)/(dt)+3y=cos(2t) is y=(2sin(2t))/(13)+(3cos(2t))/(13)+(c_{1})/(e^{3t)}