What is the integral of 1/(200-x) ?

The integral of 1/(200-x) is -ln|200-x|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/(200-x)

\int \frac{1}{200 - x} d x

- ln ∣ 200 - x ∣ + C

Solution steps

\int \frac{1}{200 - x} d x

Apply u-substitution

= \int - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - ln ∣ u ∣

Substitute back

u = 200 - x

= - ln ∣ 200 - x ∣

Add a constant to the solution

= - ln ∣ 200 - x ∣ + C