What is the derivative of x^5-20x^3+64x ?

The derivative of x^5-20x^3+64x is 5x^4-60x^2+64

What is the first derivative of x^5-20x^3+64x ?

The first derivative of x^5-20x^3+64x is 5x^4-60x^2+64

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\frac{d}{d x} (x^{5} - 20 x^{3} + 64 x)

5 x^{4} - 60 x^{2} + 64

Solution steps

\frac{d}{d x} (x^{5} - 20 x^{3} + 64 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{5}) - \frac{d}{d x} (20 x^{3}) + \frac{d}{d x} (64 x)

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (20 x^{3}) = 60 x^{2}

\frac{d}{d x} (64 x) = 64

= 5 x^{4} - 60 x^{2} + 64

What is the derivative of x^5-20x^3+64x ?
The derivative of x^5-20x^3+64x is 5x^4-60x^2+64
What is the first derivative of x^5-20x^3+64x ?
The first derivative of x^5-20x^3+64x is 5x^4-60x^2+64