What is the derivative of x\sqrt[3]{x^2} ?

The derivative of x\sqrt[3]{x^2} is \sqrt[3]{x^2}+(2x^{2/3})/3

What is the first derivative of x\sqrt[3]{x^2} ?

The first derivative of x\sqrt[3]{x^2} is \sqrt[3]{x^2}+(2x^{2/3})/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Solution steps

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

\frac{d x}{d x} = 1

Simplify

What is the derivative of x\sqrt[3]{x^2} ?
The derivative of x\sqrt[3]{x^2} is \sqrt[3]{x^2}+(2x^{2/3})/3
What is the first derivative of x\sqrt[3]{x^2} ?
The first derivative of x\sqrt[3]{x^2} is \sqrt[3]{x^2}+(2x^{2/3})/3