What is the tangent of f(x)=-1-4x^2,(3,-37) ?

The tangent of f(x)=-1-4x^2,(3,-37) is y=-24x+35

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tangent of f(x)=-1-4x^2,(3,-37)

tangent of

f (x) = - 1 - 4 x^{2}, (3, - 37)

y = - 24 x + 35

Solution steps

Find the slope of

f (x) = - 1 - 4 x^{2} : \frac{df ( x )}{d x} = - 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 24

Find the line with slope m=

- 24

and passing through

(3, - 37) : y = - 24 x + 35

y = - 24 x + 35

What is the tangent of f(x)=-1-4x^2,(3,-37) ?
The tangent of f(x)=-1-4x^2,(3,-37) is y=-24x+35