What is the integral of 2x^2-3x+2 ?

The integral of 2x^2-3x+2 is (2x^3)/3-(3x^2)/2+2x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 2x^2-3x+2

\int 2 x^{2} - 3 x + 2 d x

\frac{2 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 2 x + C

Solution steps

\int 2 x^{2} - 3 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x - \int 3 x d x + \int 2 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 2 d x = 2 x

= \frac{2 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 2 x

Add a constant to the solution

= \frac{2 x ^{3}}{3} - \frac{3 x ^{2}}{2} + 2 x + C

What is the integral of 2x^2-3x+2 ?
The integral of 2x^2-3x+2 is (2x^3)/3-(3x^2)/2+2x+C