What is the derivative of g(x)= 7/4 x^2-3x+12 ?

The derivative of g(x)= 7/4 x^2-3x+12 is (7x)/2-3

What is the first derivative of g(x)= 7/4 x^2-3x+12 ?

The first derivative of g(x)= 7/4 x^2-3x+12 is (7x)/2-3

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derivative of

g (x) = \frac{7}{4} x^{2} - 3 x + 12

\frac{7 x}{2} - 3

Solution steps

\frac{d}{d x} (\frac{7}{4} x^{2} - 3 x + 12)

Simplify

\frac{7}{4} x^{2} - 3 x + 12 : \frac{7 x ^{2}}{4} - 3 x + 12

= \frac{d}{d x} (\frac{7 x ^{2}}{4} - 3 x + 12)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{7 x ^{2}}{4}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (12)

\frac{d}{d x} (\frac{7 x ^{2}}{4}) = \frac{7 x}{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (12) = 0

= \frac{7 x}{2} - 3 + 0

Simplify

= \frac{7 x}{2} - 3

What is the derivative of g(x)= 7/4 x^2-3x+12 ?
The derivative of g(x)= 7/4 x^2-3x+12 is (7x)/2-3
What is the first derivative of g(x)= 7/4 x^2-3x+12 ?
The first derivative of g(x)= 7/4 x^2-3x+12 is (7x)/2-3