What is laplacetransform e^{5t}sin(2t) ?

The answer to laplacetransform e^{5t}sin(2t) is 2/((s-5)^2+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

laplacetransform e^{5t}sin(2t)

laplace transform

e^{5 t} sin (2 t)

\frac{2}{( s - 5 ) ^{2} + 4}

Solution steps

L {e^{5 t} sin (2 t)}

Apply transform rule:

L {f (t)} = F (s)

then

L {e^{a t} f (t)} = F (s - a)

For

e^{5 t} sin (2 t) : f (t) = sin (2 t), a = 5

= L {sin (2 t)} (s - 5)

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= \frac{2}{( s - 5 ) ^{2} + 4}

What is laplacetransform e^{5t}sin(2t) ?
The answer to laplacetransform e^{5t}sin(2t) is 2/((s-5)^2+4)