What is the derivative of 9x+1/x-4 ?

The derivative of 9x+1/x-4 is -1/(x^2)+9

What is the first derivative of 9x+1/x-4 ?

The first derivative of 9x+1/x-4 is -1/(x^2)+9

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\frac{d}{d x} (9 x + \frac{1}{x} - 4)

- \frac{1}{x ^{2}} + 9

Solution steps

\frac{d}{d x} (9 x + \frac{1}{x} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x) + \frac{d}{d x} (\frac{1}{x}) - \frac{d}{d x} (4)

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{d}{d x} (4) = 0

= 9 - \frac{1}{x ^{2}} - 0

Simplify

= - \frac{1}{x ^{2}} + 9

What is the derivative of 9x+1/x-4 ?
The derivative of 9x+1/x-4 is -1/(x^2)+9
What is the first derivative of 9x+1/x-4 ?
The first derivative of 9x+1/x-4 is -1/(x^2)+9