What is the tangent of f(x)=4x^2+2x,\at x=-2 ?

The tangent of f(x)=4x^2+2x,\at x=-2 is y=-14x-16

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tangent of f(x)=4x^2+2x,\at x=-2

tangent of

f (x) = 4 x^{2} + 2 x, at x = - 2

y = - 14 x - 16

Solution steps

Find the tangent point:

(- 2, 12)

Find the slope of

f (x) = 4 x^{2} + 2 x : \frac{df ( x )}{d x} = 8 x + 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 14

Find the line with slope m=

- 14

and passing through

(- 2, 12) : y = - 14 x - 16

y = - 14 x - 16

What is the tangent of f(x)=4x^2+2x,\at x=-2 ?
The tangent of f(x)=4x^2+2x,\at x=-2 is y=-14x-16