What is the derivative of y=(x^2+8)^2-4x ?

The derivative of y=(x^2+8)^2-4x is 4x(x^2+8)-4

What is the first derivative of y=(x^2+8)^2-4x ?

The first derivative of y=(x^2+8)^2-4x is 4x(x^2+8)-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

y = (x^{2} + 8)^{2} - 4 x

4 x (x^{2} + 8) - 4

Solution steps

\frac{d}{d x} ((x^{2} + 8)^{2} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} ((x^{2} + 8)^{2}) - \frac{d}{d x} (4 x)

\frac{d}{d x} ((x^{2} + 8)^{2}) = 4 x (x^{2} + 8)

\frac{d}{d x} (4 x) = 4

= 4 x (x^{2} + 8) - 4

What is the derivative of y=(x^2+8)^2-4x ?
The derivative of y=(x^2+8)^2-4x is 4x(x^2+8)-4
What is the first derivative of y=(x^2+8)^2-4x ?
The first derivative of y=(x^2+8)^2-4x is 4x(x^2+8)-4