What is the derivative of 230-8x+0.04x^2 ?

The derivative of 230-8x+0.04x^2 is 0.08x-8

What is the first derivative of 230-8x+0.04x^2 ?

The first derivative of 230-8x+0.04x^2 is 0.08x-8

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\frac{d}{d x} (230 - 8 x + 0.04 x^{2})

0.08 x - 8

Solution steps

\frac{d}{d x} (230 - 8 x + 0.04 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (230) - \frac{d}{d x} (8 x) + \frac{d}{d x} (0.04 x^{2})

\frac{d}{d x} (230) = 0

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (0.04 x^{2}) = 0.08 x

= 0 - 8 + 0.08 x

Simplify

= 0.08 x - 8

What is the derivative of 230-8x+0.04x^2 ?
The derivative of 230-8x+0.04x^2 is 0.08x-8
What is the first derivative of 230-8x+0.04x^2 ?
The first derivative of 230-8x+0.04x^2 is 0.08x-8