What is the integral from 0 to 1 of pi(x-x^8) ?

The integral from 0 to 1 of pi(x-x^8) is pi 7/18

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integral from 0 to 1 of pi(x-x^8)

\int_{0}^{1} π (x - x^{8}) d x

π \frac{7}{18}

Decimal

1.22173 \dots

Solution steps

\int_{0}^{1} π (x - x^{8}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{1} x - x^{8} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{0}^{1} x d x - \int_{0}^{1} x^{8} d x)

\int_{0}^{1} x d x = \frac{1}{2}

\int_{0}^{1} x^{8} d x = \frac{1}{9}

= π (\frac{1}{2} - \frac{1}{9})

Join

\frac{1}{2} - \frac{1}{9} : \frac{7}{18}

= π \frac{7}{18}

What is the integral from 0 to 1 of pi(x-x^8) ?
The integral from 0 to 1 of pi(x-x^8) is pi 7/18