What is the derivative of sqrt(1+36x) ?

The derivative of sqrt(1+36x) is (18)/(sqrt(1+36x))

What is the first derivative of sqrt(1+36x) ?

The first derivative of sqrt(1+36x) is (18)/(sqrt(1+36x))

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\frac{d}{d x} (1 + 36 x)

\frac{18}{1 + 36 x}

Solution steps

\frac{d}{d x} (1 + 36 x)

Apply the chain rule:

\frac{1}{2 1 + 36 x} \frac{d}{d x} (1 + 36 x)

= \frac{1}{2 1 + 36 x} \frac{d}{d x} (1 + 36 x)

\frac{d}{d x} (1 + 36 x) = 36

= \frac{1}{2 1 + 36 x} \cdot 36

Simplify

\frac{1}{2 1 + 36 x} \cdot 36 : \frac{18}{1 + 36 x}

= \frac{18}{1 + 36 x}

What is the derivative of sqrt(1+36x) ?
The derivative of sqrt(1+36x) is (18)/(sqrt(1+36x))
What is the first derivative of sqrt(1+36x) ?
The first derivative of sqrt(1+36x) is (18)/(sqrt(1+36x))